5(x-4)-(5x+2)=2(2x-2)-22

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Solution for 5(x-4)-(5x+2)=2(2x-2)-22 equation: 



5(x-4)-(5x+2)=2(2x-2)-22

We move all terms to the left:

5(x-4)-(5x+2)-(2(2x-2)-22)=0

We multiply parentheses

5x-(5x+2)-(2(2x-2)-22)-20=0

We get rid of parentheses

5x-5x-(2(2x-2)-22)-2-20=0



We calculate terms in parentheses: -(2(2x-2)-22), so:

2(2x-2)-22

We multiply parentheses

4x-4-22

We add all the numbers together, and all the variables

4x-26

Back to the equation:

-(4x-26)



We add all the numbers together, and all the variables

-(4x-26)-22=0

We get rid of parentheses

-4x+26-22=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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