5(x-4)-(5x+2)=2(2x-2)-22

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Solution for 5(x-4)-(5x+2)=2(2x-2)-22 equation:



5(x-4)-(5x+2)=2(2x-2)-22
We move all terms to the left:
5(x-4)-(5x+2)-(2(2x-2)-22)=0
We multiply parentheses
5x-(5x+2)-(2(2x-2)-22)-20=0
We get rid of parentheses
5x-5x-(2(2x-2)-22)-2-20=0
We calculate terms in parentheses: -(2(2x-2)-22), so:
2(2x-2)-22
We multiply parentheses
4x-4-22
We add all the numbers together, and all the variables
4x-26
Back to the equation:
-(4x-26)
We add all the numbers together, and all the variables
-(4x-26)-22=0
We get rid of parentheses
-4x+26-22=0
We add all the numbers together, and all the variables
-4x+4=0
We move all terms containing x to the left, all other terms to the right
-4x=-4
x=-4/-4
x=1

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