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5(x-4)-2x=3(x-6)-2
We move all terms to the left:
5(x-4)-2x-(3(x-6)-2)=0
We add all the numbers together, and all the variables
-2x+5(x-4)-(3(x-6)-2)=0
We multiply parentheses
-2x+5x-(3(x-6)-2)-20=0
We calculate terms in parentheses: -(3(x-6)-2), so:We add all the numbers together, and all the variables
3(x-6)-2
We multiply parentheses
3x-18-2
We add all the numbers together, and all the variables
3x-20
Back to the equation:
-(3x-20)
3x-(3x-20)-20=0
We get rid of parentheses
3x-3x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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