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5(x-4)-5=2(x-20)
We move all terms to the left:
5(x-4)-5-(2(x-20))=0
We multiply parentheses
5x-(2(x-20))-20-5=0
We calculate terms in parentheses: -(2(x-20)), so:We add all the numbers together, and all the variables
2(x-20)
We multiply parentheses
2x-40
Back to the equation:
-(2x-40)
5x-(2x-40)-25=0
We get rid of parentheses
5x-2x+40-25=0
We add all the numbers together, and all the variables
3x+15=0
We move all terms containing x to the left, all other terms to the right
3x=-15
x=-15/3
x=-5
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