5(x-4)-7=2+3(5+x)

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Solution for 5(x-4)-7=2+3(5+x) equation: 



5(x-4)-7=2+3(5+x)

We move all terms to the left:

5(x-4)-7-(2+3(5+x))=0

We add all the numbers together, and all the variables

5(x-4)-(2+3(x+5))-7=0

We multiply parentheses

5x-(2+3(x+5))-20-7=0



We calculate terms in parentheses: -(2+3(x+5)), so:

2+3(x+5)

determiningTheFunctionDomain
3(x+5)+2

We multiply parentheses

3x+15+2

We add all the numbers together, and all the variables

3x+17

Back to the equation:

-(3x+17)



We add all the numbers together, and all the variables

5x-(3x+17)-27=0

We get rid of parentheses

5x-3x-17-27=0

We add all the numbers together, and all the variables

2x-44=0

We move all terms containing x to the left, all other terms to the right

2x=44

x=44/2

x=22

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