5(x-4)-8x=7x-2(4x-5)

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Solution for 5(x-4)-8x=7x-2(4x-5) equation: 



5(x-4)-8x=7x-2(4x-5)

We move all terms to the left:

5(x-4)-8x-(7x-2(4x-5))=0

We add all the numbers together, and all the variables

-8x+5(x-4)-(7x-2(4x-5))=0

We multiply parentheses

-8x+5x-(7x-2(4x-5))-20=0



We calculate terms in parentheses: -(7x-2(4x-5)), so:

7x-2(4x-5)

We multiply parentheses

7x-8x+10

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

-3x-(-1x+10)-20=0

We get rid of parentheses

-3x+1x-10-20=0

We add all the numbers together, and all the variables

-2x-30=0

We move all terms containing x to the left, all other terms to the right

-2x=30

x=30/-2

x=-15

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