5(x-4)=(4x+7)

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Solution for 5(x-4)=(4x+7) equation: 



5(x-4)=(4x+7)

We move all terms to the left:

5(x-4)-((4x+7))=0

We multiply parentheses

5x-((4x+7))-20=0



We calculate terms in parentheses: -((4x+7)), so:

(4x+7)

We get rid of parentheses

4x+7

Back to the equation:

-(4x+7)



We get rid of parentheses

5x-4x-7-20=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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