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5(x-4)=(x-5)
We move all terms to the left:
5(x-4)-((x-5))=0
We multiply parentheses
5x-((x-5))-20=0
We calculate terms in parentheses: -((x-5)), so:We get rid of parentheses
(x-5)
We get rid of parentheses
x-5
Back to the equation:
-(x-5)
5x-x+5-20=0
We add all the numbers together, and all the variables
4x-15=0
We move all terms containing x to the left, all other terms to the right
4x=15
x=15/4
x=3+3/4
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