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5(x-4)=2(4-x)
We move all terms to the left:
5(x-4)-(2(4-x))=0
We add all the numbers together, and all the variables
5(x-4)-(2(-1x+4))=0
We multiply parentheses
5x-(2(-1x+4))-20=0
We calculate terms in parentheses: -(2(-1x+4)), so:We get rid of parentheses
2(-1x+4)
We multiply parentheses
-2x+8
Back to the equation:
-(-2x+8)
5x+2x-8-20=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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