5(x-4)=2(x-6)+10

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Solution for 5(x-4)=2(x-6)+10 equation: 



5(x-4)=2(x-6)+10

We move all terms to the left:

5(x-4)-(2(x-6)+10)=0

We multiply parentheses

5x-(2(x-6)+10)-20=0



We calculate terms in parentheses: -(2(x-6)+10), so:

2(x-6)+10

We multiply parentheses

2x-12+10

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

5x-2x+2-20=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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