5(x-4)=3(-x+2)

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Solution for 5(x-4)=3(-x+2) equation: 



5(x-4)=3(-x+2)

We move all terms to the left:

5(x-4)-(3(-x+2))=0

We add all the numbers together, and all the variables

5(x-4)-(3(-1x+2))=0

We multiply parentheses

5x-(3(-1x+2))-20=0



We calculate terms in parentheses: -(3(-1x+2)), so:

3(-1x+2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

5x+3x-6-20=0

We add all the numbers together, and all the variables

8x-26=0

We move all terms containing x to the left, all other terms to the right

8x=26

x=26/8

x=3+1/4

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