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5(x-4)=3-(2x-5)
We move all terms to the left:
5(x-4)-(3-(2x-5))=0
We multiply parentheses
5x-(3-(2x-5))-20=0
We calculate terms in parentheses: -(3-(2x-5)), so:We get rid of parentheses
3-(2x-5)
determiningTheFunctionDomain -(2x-5)+3
We get rid of parentheses
-2x+5+3
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
5x+2x-8-20=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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