5(x-4)=47

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Solution for 5(x-4)=47 equation: 



5(x-4)=47

We move all terms to the left:

5(x-4)-(47)=0

We multiply parentheses

5x-20-47=0

We add all the numbers together, and all the variables

5x-67=0

We move all terms containing x to the left, all other terms to the right

5x=67

x=67/5

x=13+2/5

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