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5(x-4)=5(x+1)-3
We move all terms to the left:
5(x-4)-(5(x+1)-3)=0
We multiply parentheses
5x-(5(x+1)-3)-20=0
We calculate terms in parentheses: -(5(x+1)-3), so:We get rid of parentheses
5(x+1)-3
We multiply parentheses
5x+5-3
We add all the numbers together, and all the variables
5x+2
Back to the equation:
-(5x+2)
5x-5x-2-20=0
We add all the numbers together, and all the variables
-22!=0
There is no solution for this equation
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