5(x-4)=7(x+3)-2(x+1)

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Solution for 5(x-4)=7(x+3)-2(x+1) equation: 



5(x-4)=7(x+3)-2(x+1)

We move all terms to the left:

5(x-4)-(7(x+3)-2(x+1))=0

We multiply parentheses

5x-(7(x+3)-2(x+1))-20=0



We calculate terms in parentheses: -(7(x+3)-2(x+1)), so:

7(x+3)-2(x+1)

We multiply parentheses

7x-2x+21-2

We add all the numbers together, and all the variables

5x+19

Back to the equation:

-(5x+19)



We get rid of parentheses

5x-5x-19-20=0

We add all the numbers together, and all the variables

-39!=0

There is no solution for this equation

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