5(x-4)=8x-47

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Solution for 5(x-4)=8x-47 equation: 



5(x-4)=8x-47

We move all terms to the left:

5(x-4)-(8x-47)=0

We multiply parentheses

5x-(8x-47)-20=0

We get rid of parentheses

5x-8x+47-20=0

We add all the numbers together, and all the variables

-3x+27=0

We move all terms containing x to the left, all other terms to the right

-3x=-27

x=-27/-3

x=+9

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