5(x-5)+(x-4)=10+16(x-10)

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Solution for 5(x-5)+(x-4)=10+16(x-10) equation: 



5(x-5)+(x-4)=10+16(x-10)

We move all terms to the left:

5(x-5)+(x-4)-(10+16(x-10))=0

We multiply parentheses

5x+(x-4)-(10+16(x-10))-25=0

We get rid of parentheses

5x+x-(10+16(x-10))-4-25=0



We calculate terms in parentheses: -(10+16(x-10)), so:

10+16(x-10)

determiningTheFunctionDomain
16(x-10)+10

We multiply parentheses

16x-160+10

We add all the numbers together, and all the variables

16x-150

Back to the equation:

-(16x-150)



We add all the numbers together, and all the variables

6x-(16x-150)-29=0

We get rid of parentheses

6x-16x+150-29=0

We add all the numbers together, and all the variables

-10x+121=0

We move all terms containing x to the left, all other terms to the right

-10x=-121

x=-121/-10

x=12+1/10

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