5(x-5)+6=4-6(x-2)

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Solution for 5(x-5)+6=4-6(x-2) equation: 



5(x-5)+6=4-6(x-2)

We move all terms to the left:

5(x-5)+6-(4-6(x-2))=0

We multiply parentheses

5x-(4-6(x-2))-25+6=0



We calculate terms in parentheses: -(4-6(x-2)), so:

4-6(x-2)

determiningTheFunctionDomain
-6(x-2)+4

We multiply parentheses

-6x+12+4

We add all the numbers together, and all the variables

-6x+16

Back to the equation:

-(-6x+16)



We add all the numbers together, and all the variables

5x-(-6x+16)-19=0

We get rid of parentheses

5x+6x-16-19=0

We add all the numbers together, and all the variables

11x-35=0

We move all terms containing x to the left, all other terms to the right

11x=35

x=35/11

x=3+2/11

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