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5(x-5)=4(x+20)
We move all terms to the left:
5(x-5)-(4(x+20))=0
We multiply parentheses
5x-(4(x+20))-25=0
We calculate terms in parentheses: -(4(x+20)), so:We get rid of parentheses
4(x+20)
We multiply parentheses
4x+80
Back to the equation:
-(4x+80)
5x-4x-80-25=0
We add all the numbers together, and all the variables
x-105=0
We move all terms containing x to the left, all other terms to the right
x=105
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