5(x-6)+30-4x=-7(x-3)+7x-20

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Solution for 5(x-6)+30-4x=-7(x-3)+7x-20 equation: 



5(x-6)+30-4x=-7(x-3)+7x-20

We move all terms to the left:

5(x-6)+30-4x-(-7(x-3)+7x-20)=0

We add all the numbers together, and all the variables

-4x+5(x-6)-(-7(x-3)+7x-20)+30=0

We multiply parentheses

-4x+5x-(-7(x-3)+7x-20)-30+30=0



We calculate terms in parentheses: -(-7(x-3)+7x-20), so:

-7(x-3)+7x-20

We add all the numbers together, and all the variables

7x-7(x-3)-20

We multiply parentheses

7x-7x+21-20

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)



We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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