5(x-6)+30-4x=-7(x-3)+7x-20

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Solution for 5(x-6)+30-4x=-7(x-3)+7x-20 equation:



5(x-6)+30-4x=-7(x-3)+7x-20
We move all terms to the left:
5(x-6)+30-4x-(-7(x-3)+7x-20)=0
We add all the numbers together, and all the variables
-4x+5(x-6)-(-7(x-3)+7x-20)+30=0
We multiply parentheses
-4x+5x-(-7(x-3)+7x-20)-30+30=0
We calculate terms in parentheses: -(-7(x-3)+7x-20), so:
-7(x-3)+7x-20
We add all the numbers together, and all the variables
7x-7(x-3)-20
We multiply parentheses
7x-7x+21-20
We add all the numbers together, and all the variables
1
Back to the equation:
-(1)
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1

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