5(x-6)=2+(x+3)

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Solution for 5(x-6)=2+(x+3) equation: 



5(x-6)=2+(x+3)

We move all terms to the left:

5(x-6)-(2+(x+3))=0

We multiply parentheses

5x-(2+(x+3))-30=0



We calculate terms in parentheses: -(2+(x+3)), so:

2+(x+3)

determiningTheFunctionDomain
(x+3)+2

We get rid of parentheses

x+3+2

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

5x-x-5-30=0

We add all the numbers together, and all the variables

4x-35=0

We move all terms containing x to the left, all other terms to the right

4x=35

x=35/4

x=8+3/4

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