5(x-7)+19=2(x-5)

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Solution for 5(x-7)+19=2(x-5) equation: 



5(x-7)+19=2(x-5)

We move all terms to the left:

5(x-7)+19-(2(x-5))=0

We multiply parentheses

5x-(2(x-5))-35+19=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

5x-(2x-10)-16=0

We get rid of parentheses

5x-2x+10-16=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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