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5(x-7)=3(3-2x)
We move all terms to the left:
5(x-7)-(3(3-2x))=0
We add all the numbers together, and all the variables
5(x-7)-(3(-2x+3))=0
We multiply parentheses
5x-(3(-2x+3))-35=0
We calculate terms in parentheses: -(3(-2x+3)), so:We get rid of parentheses
3(-2x+3)
We multiply parentheses
-6x+9
Back to the equation:
-(-6x+9)
5x+6x-9-35=0
We add all the numbers together, and all the variables
11x-44=0
We move all terms containing x to the left, all other terms to the right
11x=44
x=44/11
x=4
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