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5(x-7)=3(x+11)
We move all terms to the left:
5(x-7)-(3(x+11))=0
We multiply parentheses
5x-(3(x+11))-35=0
We calculate terms in parentheses: -(3(x+11)), so:We get rid of parentheses
3(x+11)
We multiply parentheses
3x+33
Back to the equation:
-(3x+33)
5x-3x-33-35=0
We add all the numbers together, and all the variables
2x-68=0
We move all terms containing x to the left, all other terms to the right
2x=68
x=68/2
x=34
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