5(x-8)+20=3(x-4)

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Solution for 5(x-8)+20=3(x-4) equation:


Simplifying
5(x + -8) + 20 = 3(x + -4)

Reorder the terms:
5(-8 + x) + 20 = 3(x + -4)
(-8 * 5 + x * 5) + 20 = 3(x + -4)
(-40 + 5x) + 20 = 3(x + -4)

Reorder the terms:
-40 + 20 + 5x = 3(x + -4)

Combine like terms: -40 + 20 = -20
-20 + 5x = 3(x + -4)

Reorder the terms:
-20 + 5x = 3(-4 + x)
-20 + 5x = (-4 * 3 + x * 3)
-20 + 5x = (-12 + 3x)

Solving
-20 + 5x = -12 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
-20 + 5x + -3x = -12 + 3x + -3x

Combine like terms: 5x + -3x = 2x
-20 + 2x = -12 + 3x + -3x

Combine like terms: 3x + -3x = 0
-20 + 2x = -12 + 0
-20 + 2x = -12

Add '20' to each side of the equation.
-20 + 20 + 2x = -12 + 20

Combine like terms: -20 + 20 = 0
0 + 2x = -12 + 20
2x = -12 + 20

Combine like terms: -12 + 20 = 8
2x = 8

Divide each side by '2'.
x = 4

Simplifying
x = 4

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