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5(x-8)+27=2(x-5)
We move all terms to the left:
5(x-8)+27-(2(x-5))=0
We multiply parentheses
5x-(2(x-5))-40+27=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
5x-(2x-10)-13=0
We get rid of parentheses
5x-2x+10-13=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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