5(x-9+4x-5)=65-2(4-x)

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Solution for 5(x-9+4x-5)=65-2(4-x) equation: 



5(x-9+4x-5)=65-2(4-x)

We move all terms to the left:

5(x-9+4x-5)-(65-2(4-x))=0

We add all the numbers together, and all the variables

5(5x-14)-(65-2(-1x+4))=0

We multiply parentheses

25x-(65-2(-1x+4))-70=0



We calculate terms in parentheses: -(65-2(-1x+4)), so:

65-2(-1x+4)

determiningTheFunctionDomain
-2(-1x+4)+65

We multiply parentheses

2x-8+65

We add all the numbers together, and all the variables

2x+57

Back to the equation:

-(2x+57)



We get rid of parentheses

25x-2x-57-70=0

We add all the numbers together, and all the variables

23x-127=0

We move all terms containing x to the left, all other terms to the right

23x=127

x=127/23

x=5+12/23

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