5(x2)-3x=2(x-3)-16

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Solution for 5(x2)-3x=2(x-3)-16 equation: 



5(x2)-3x=2(x-3)-16

We move all terms to the left:

5(x2)-3x-(2(x-3)-16)=0

We add all the numbers together, and all the variables

5x^2-3x-(2(x-3)-16)=0



We calculate terms in parentheses: -(2(x-3)-16), so:

2(x-3)-16

We multiply parentheses

2x-6-16

We add all the numbers together, and all the variables

2x-22

Back to the equation:

-(2x-22)



We get rid of parentheses

5x^2-3x-2x+22=0

We add all the numbers together, and all the variables

5x^2-5x+22=0

a = 5; b = -5; c = +22;
Δ = b2-4ac
Δ = -52-4·5·22
Δ = -415
Delta is less than zero, so there is no solution for the equation

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