5(x2)=x+6(x-3)

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Solution for 5(x2)=x+6(x-3) equation: 



5(x2)=x+6(x-3)

We move all terms to the left:

5(x2)-(x+6(x-3))=0

We add all the numbers together, and all the variables

5x^2-(x+6(x-3))=0



We calculate terms in parentheses: -(x+6(x-3)), so:

x+6(x-3)

We multiply parentheses

x+6x-18

We add all the numbers together, and all the variables

7x-18

Back to the equation:

-(7x-18)



We get rid of parentheses

5x^2-7x+18=0

a = 5; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·5·18
Δ = -311
Delta is less than zero, so there is no solution for the equation

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