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5(x2+2x)=73.
We move all terms to the left:
5(x2+2x)-(73.)=0
We add all the numbers together, and all the variables
5(+x^2+2x)-73=0
We multiply parentheses
5x^2+10x-73=0
a = 5; b = 10; c = -73;
Δ = b2-4ac
Δ = 102-4·5·(-73)
Δ = 1560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1560}=\sqrt{4*390}=\sqrt{4}*\sqrt{390}=2\sqrt{390}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{390}}{2*5}=\frac{-10-2\sqrt{390}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{390}}{2*5}=\frac{-10+2\sqrt{390}}{10} $
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