5(x2+x2)+2=7(x2+x2+1)

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Solution for 5(x2+x2)+2=7(x2+x2+1) equation: 



5(x2+x2)+2=7(x2+x2+1)

We move all terms to the left:

5(x2+x2)+2-(7(x2+x2+1))=0

We add all the numbers together, and all the variables

5(+2x^2)-(7(+2x^2+1))+2=0

We multiply parentheses

10x^2-(7(+2x^2+1))+2=0



We calculate terms in parentheses: -(7(+2x^2+1)), so:

7(+2x^2+1)

We multiply parentheses

14x^2+7

Back to the equation:

-(14x^2+7)



We get rid of parentheses

10x^2-14x^2-7+2=0

We add all the numbers together, and all the variables

-4x^2-5=0

a = -4; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-4)·(-5)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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