5(y+1)+2=8(y-1)+3

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Solution for 5(y+1)+2=8(y-1)+3 equation: 



5(y+1)+2=8(y-1)+3

We move all terms to the left:

5(y+1)+2-(8(y-1)+3)=0

We multiply parentheses

5y-(8(y-1)+3)+5+2=0



We calculate terms in parentheses: -(8(y-1)+3), so:

8(y-1)+3

We multiply parentheses

8y-8+3

We add all the numbers together, and all the variables

8y-5

Back to the equation:

-(8y-5)



We add all the numbers together, and all the variables

5y-(8y-5)+7=0

We get rid of parentheses

5y-8y+5+7=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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