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5(y+1)-3(3y-5)=20-4y
We move all terms to the left:
5(y+1)-3(3y-5)-(20-4y)=0
We add all the numbers together, and all the variables
5(y+1)-3(3y-5)-(-4y+20)=0
We multiply parentheses
5y-9y-(-4y+20)+5+15=0
We get rid of parentheses
5y-9y+4y-20+5+15=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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