5(y+1)-8=5y(2-4)

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Solution for 5(y+1)-8=5y(2-4) equation:


Simplifying
5(y + 1) + -8 = 5y(2 + -4)

Reorder the terms:
5(1 + y) + -8 = 5y(2 + -4)
(1 * 5 + y * 5) + -8 = 5y(2 + -4)
(5 + 5y) + -8 = 5y(2 + -4)

Reorder the terms:
5 + -8 + 5y = 5y(2 + -4)

Combine like terms: 5 + -8 = -3
-3 + 5y = 5y(2 + -4)

Combine like terms: 2 + -4 = -2
-3 + 5y = 5y(-2)

Reorder the terms for easier multiplication:
-3 + 5y = 5 * -2y

Multiply 5 * -2
-3 + 5y = -10y

Solving
-3 + 5y = -10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10y' to each side of the equation.
-3 + 5y + 10y = -10y + 10y

Combine like terms: 5y + 10y = 15y
-3 + 15y = -10y + 10y

Combine like terms: -10y + 10y = 0
-3 + 15y = 0

Add '3' to each side of the equation.
-3 + 3 + 15y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 15y = 0 + 3
15y = 0 + 3

Combine like terms: 0 + 3 = 3
15y = 3

Divide each side by '15'.
y = 0.2

Simplifying
y = 0.2

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