5(y+1)=27

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Solution for 5(y+1)=27 equation: 



5(y+1)=27

We move all terms to the left:

5(y+1)-(27)=0

We multiply parentheses

5y+5-27=0

We add all the numbers together, and all the variables

5y-22=0

We move all terms containing y to the left, all other terms to the right

5y=22

y=22/5

y=4+2/5

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