5(y+1)=27

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Solution for 5(y+1)=27 equation:



5(y+1)=27
We move all terms to the left:
5(y+1)-(27)=0
We multiply parentheses
5y+5-27=0
We add all the numbers together, and all the variables
5y-22=0
We move all terms containing y to the left, all other terms to the right
5y=22
y=22/5
y=4+2/5

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