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5(y+1)=3(y+2)
We move all terms to the left:
5(y+1)-(3(y+2))=0
We multiply parentheses
5y-(3(y+2))+5=0
We calculate terms in parentheses: -(3(y+2)), so:We get rid of parentheses
3(y+2)
We multiply parentheses
3y+6
Back to the equation:
-(3y+6)
5y-3y-6+5=0
We add all the numbers together, and all the variables
2y-1=0
We move all terms containing y to the left, all other terms to the right
2y=1
y=1/2
y=1/2
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