5(y+1)=3(y+2)

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Solution for 5(y+1)=3(y+2) equation: 



5(y+1)=3(y+2)

We move all terms to the left:

5(y+1)-(3(y+2))=0

We multiply parentheses

5y-(3(y+2))+5=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

5y-3y-6+5=0

We add all the numbers together, and all the variables

2y-1=0

We move all terms containing y to the left, all other terms to the right

2y=1

y=1/2

y=1/2

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