5(y+1)=3(y-1)+2y

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Solution for 5(y+1)=3(y-1)+2y equation: 



5(y+1)=3(y-1)+2y

We move all terms to the left:

5(y+1)-(3(y-1)+2y)=0

We multiply parentheses

5y-(3(y-1)+2y)+5=0



We calculate terms in parentheses: -(3(y-1)+2y), so:

3(y-1)+2y

We add all the numbers together, and all the variables

2y+3(y-1)

We multiply parentheses

2y+3y-3

We add all the numbers together, and all the variables

5y-3

Back to the equation:

-(5y-3)



We get rid of parentheses

5y-5y+3+5=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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