5(y+1)=y=3(y-1)+7

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Solution for 5(y+1)=y=3(y-1)+7 equation: 



5(y+1)=y=3(y-1)+7

We move all terms to the left:

5(y+1)-(y)=0

We add all the numbers together, and all the variables

-1y+5(y+1)=0

We multiply parentheses

-1y+5y+5=0

We add all the numbers together, and all the variables

4y+5=0

We move all terms containing y to the left, all other terms to the right

4y=-5

y=-5/4

y=-1+1/4

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