5(y+12)=-3(y-2)

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Solution for 5(y+12)=-3(y-2) equation:



5(y+12)=-3(y-2)
We move all terms to the left:
5(y+12)-(-3(y-2))=0
We multiply parentheses
5y-(-3(y-2))+60=0
We calculate terms in parentheses: -(-3(y-2)), so:
-3(y-2)
We multiply parentheses
-3y+6
Back to the equation:
-(-3y+6)
We get rid of parentheses
5y+3y-6+60=0
We add all the numbers together, and all the variables
8y+54=0
We move all terms containing y to the left, all other terms to the right
8y=-54
y=-54/8
y=-6+3/4

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