5(y+2)+3(y-4)=

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Solution for 5(y+2)+3(y-4)= equation:


Simplifying
5(y + 2) + 3(y + -4) = 0

Reorder the terms:
5(2 + y) + 3(y + -4) = 0
(2 * 5 + y * 5) + 3(y + -4) = 0
(10 + 5y) + 3(y + -4) = 0

Reorder the terms:
10 + 5y + 3(-4 + y) = 0
10 + 5y + (-4 * 3 + y * 3) = 0
10 + 5y + (-12 + 3y) = 0

Reorder the terms:
10 + -12 + 5y + 3y = 0

Combine like terms: 10 + -12 = -2
-2 + 5y + 3y = 0

Combine like terms: 5y + 3y = 8y
-2 + 8y = 0

Solving
-2 + 8y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 8y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 8y = 0 + 2
8y = 0 + 2

Combine like terms: 0 + 2 = 2
8y = 2

Divide each side by '8'.
y = 0.25

Simplifying
y = 0.25

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