5(y+2)+3y=2(y+5)

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Solution for 5(y+2)+3y=2(y+5) equation: 



5(y+2)+3y=2(y+5)

We move all terms to the left:

5(y+2)+3y-(2(y+5))=0

We add all the numbers together, and all the variables

3y+5(y+2)-(2(y+5))=0

We multiply parentheses

3y+5y-(2(y+5))+10=0



We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)



We add all the numbers together, and all the variables

8y-(2y+10)+10=0

We get rid of parentheses

8y-2y-10+10=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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