5(y+2)+y=3(y-1)+1

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Solution for 5(y+2)+y=3(y-1)+1 equation: 


Simplifying
5(y + 2) + y = 3(y + -1) + 1

Reorder the terms:
5(2 + y) + y = 3(y + -1) + 1
(2 * 5 + y * 5) + y = 3(y + -1) + 1
(10 + 5y) + y = 3(y + -1) + 1

Combine like terms: 5y + y = 6y
10 + 6y = 3(y + -1) + 1

Reorder the terms:
10 + 6y = 3(-1 + y) + 1
10 + 6y = (-1 * 3 + y * 3) + 1
10 + 6y = (-3 + 3y) + 1

Reorder the terms:
10 + 6y = -3 + 1 + 3y

Combine like terms: -3 + 1 = -2
10 + 6y = -2 + 3y

Solving
10 + 6y = -2 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
10 + 6y + -3y = -2 + 3y + -3y

Combine like terms: 6y + -3y = 3y
10 + 3y = -2 + 3y + -3y

Combine like terms: 3y + -3y = 0
10 + 3y = -2 + 0
10 + 3y = -2

Add '-10' to each side of the equation.
10 + -10 + 3y = -2 + -10

Combine like terms: 10 + -10 = 0
0 + 3y = -2 + -10
3y = -2 + -10

Combine like terms: -2 + -10 = -12
3y = -12

Divide each side by '3'.
y = -4

Simplifying
y = -4

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