5(y+2)-(-y-1)=3

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Solution for 5(y+2)-(-y-1)=3 equation: 



5(y+2)-(-y-1)=3

We move all terms to the left:

5(y+2)-(-y-1)-(3)=0

We add all the numbers together, and all the variables

5(y+2)-(-1y-1)-3=0

We multiply parentheses

5y-(-1y-1)+10-3=0

We get rid of parentheses

5y+1y+1+10-3=0

We add all the numbers together, and all the variables

6y+8=0

We move all terms containing y to the left, all other terms to the right

6y=-8

y=-8/6

y=-1+1/3

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