5(y+2)-4(y-1)=6

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Solution for 5(y+2)-4(y-1)=6 equation:


Simplifying
5(y + 2) + -4(y + -1) = 6

Reorder the terms:
5(2 + y) + -4(y + -1) = 6
(2 * 5 + y * 5) + -4(y + -1) = 6
(10 + 5y) + -4(y + -1) = 6

Reorder the terms:
10 + 5y + -4(-1 + y) = 6
10 + 5y + (-1 * -4 + y * -4) = 6
10 + 5y + (4 + -4y) = 6

Reorder the terms:
10 + 4 + 5y + -4y = 6

Combine like terms: 10 + 4 = 14
14 + 5y + -4y = 6

Combine like terms: 5y + -4y = 1y
14 + 1y = 6

Solving
14 + 1y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 1y = 6 + -14

Combine like terms: 14 + -14 = 0
0 + 1y = 6 + -14
1y = 6 + -14

Combine like terms: 6 + -14 = -8
1y = -8

Divide each side by '1'.
y = -8

Simplifying
y = -8

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