5(y+2)-4y=-(2+y)

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Solution for 5(y+2)-4y=-(2+y) equation: 



5(y+2)-4y=-(2+y)

We move all terms to the left:

5(y+2)-4y-(-(2+y))=0

We add all the numbers together, and all the variables

5(y+2)-4y-(-(y+2))=0

We add all the numbers together, and all the variables

-4y+5(y+2)-(-(y+2))=0

We multiply parentheses

-4y+5y-(-(y+2))+10=0



We calculate terms in parentheses: -(-(y+2)), so:

-(y+2)

We get rid of parentheses

-y-2

We add all the numbers together, and all the variables

-1y-2

Back to the equation:

-(-1y-2)



We add all the numbers together, and all the variables

y-(-1y-2)+10=0

We get rid of parentheses

y+1y+2+10=0

We add all the numbers together, and all the variables

2y+12=0

We move all terms containing y to the left, all other terms to the right

2y=-12

y=-12/2

y=-6

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