5(y+2)-6y(y-1)=11y+16-12y

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Solution for 5(y+2)-6y(y-1)=11y+16-12y equation: 



5(y+2)-6y(y-1)=11y+16-12y

We move all terms to the left:

5(y+2)-6y(y-1)-(11y+16-12y)=0

We add all the numbers together, and all the variables

5(y+2)-6y(y-1)-(-1y+16)=0

We multiply parentheses

-6y^2+5y+6y-(-1y+16)+10=0

We get rid of parentheses

-6y^2+5y+6y+1y-16+10=0

We add all the numbers together, and all the variables

-6y^2+12y-6=0

a = -6; b = 12; c = -6;
Δ = b2-4ac
Δ = 122-4·(-6)·(-6)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-12}{-12}=1$

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