5(y+2)=+18-(1-3y)

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Solution for 5(y+2)=+18-(1-3y) equation: 



5(y+2)=+18-(1-3y)

We move all terms to the left:

5(y+2)-(+18-(1-3y))=0

We add all the numbers together, and all the variables

5(y+2)-(+18-(-3y+1))=0

We multiply parentheses

5y-(+18-(-3y+1))+10=0



We calculate terms in parentheses: -(+18-(-3y+1)), so:

+18-(-3y+1)

determiningTheFunctionDomain
-(-3y+1)+18

We get rid of parentheses

3y-1+18

We add all the numbers together, and all the variables

3y+17

Back to the equation:

-(3y+17)



We get rid of parentheses

5y-3y-17+10=0

We add all the numbers together, and all the variables

2y-7=0

We move all terms containing y to the left, all other terms to the right

2y=7

y=7/2

y=3+1/2

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