5(y+2)=+8-(1-3y)

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Solution for 5(y+2)=+8-(1-3y) equation: 



5(y+2)=+8-(1-3y)

We move all terms to the left:

5(y+2)-(+8-(1-3y))=0

We add all the numbers together, and all the variables

5(y+2)-(+8-(-3y+1))=0

We multiply parentheses

5y-(+8-(-3y+1))+10=0



We calculate terms in parentheses: -(+8-(-3y+1)), so:

+8-(-3y+1)

determiningTheFunctionDomain
-(-3y+1)+8

We get rid of parentheses

3y-1+8

We add all the numbers together, and all the variables

3y+7

Back to the equation:

-(3y+7)



We get rid of parentheses

5y-3y-7+10=0

We add all the numbers together, and all the variables

2y+3=0

We move all terms containing y to the left, all other terms to the right

2y=-3

y=-3/2

y=-1+1/2

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