5(y+2)=-3(5y-4)+8y

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Solution for 5(y+2)=-3(5y-4)+8y equation: 



5(y+2)=-3(5y-4)+8y

We move all terms to the left:

5(y+2)-(-3(5y-4)+8y)=0

We multiply parentheses

5y-(-3(5y-4)+8y)+10=0



We calculate terms in parentheses: -(-3(5y-4)+8y), so:

-3(5y-4)+8y

We add all the numbers together, and all the variables

8y-3(5y-4)

We multiply parentheses

8y-15y+12

We add all the numbers together, and all the variables

-7y+12

Back to the equation:

-(-7y+12)



We get rid of parentheses

5y+7y-12+10=0

We add all the numbers together, and all the variables

12y-2=0

We move all terms containing y to the left, all other terms to the right

12y=2

y=2/12

y=1/6

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