5(y+2)=1/10(30y+40)

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Solution for 5(y+2)=1/10(30y+40) equation: 



5(y+2)=1/10(30y+40)

We move all terms to the left:

5(y+2)-(1/10(30y+40))=0



Domain of the equation: 10(30y+40))!=0

y∈R



We multiply parentheses

5y-(1/10(30y+40))+10=0

We multiply all the terms by the denominator


5y*10(30y+40))-(1+10*10(30y+40))=0

Wy multiply elements

50y^2(3+100y(3=0

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