5(y+2)=2(2y-1)

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Solution for 5(y+2)=2(2y-1) equation: 



5(y+2)=2(2y-1)

We move all terms to the left:

5(y+2)-(2(2y-1))=0

We multiply parentheses

5y-(2(2y-1))+10=0



We calculate terms in parentheses: -(2(2y-1)), so:

2(2y-1)

We multiply parentheses

4y-2

Back to the equation:

-(4y-2)



We get rid of parentheses

5y-4y+2+10=0

We add all the numbers together, and all the variables

y+12=0

We move all terms containing y to the left, all other terms to the right

y=-12

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